# Line slope calculator 2x-5y=-12

**Straight line given by points A[4; 4] and B[9; 6]**

## Calculation:

**Slope-intercept form of line:**y = 0.4x+2.4

**Canonical form of the line equation:**2x-5y+12 = 0

**Parametric form of the line equation:**

x = 5t+4

y = 2t+4 ; t ∈ R

**Slope:**m = 0.4

**Slope angle of line: φ =**21°48'5″ = 0.3805 rad

**X intercept:**x

_{0}= -6

**Y intercept:**y

_{0}= q = 2.4

**Distance line from the origin:**d

_{0}= 2.2283

**The length of the segment AB: |AB| =**5.3852

**Vector: AB =**(5; 2)

**Normal vector: n =**(2; -5)

**Midpoint of the segment AB: M =**[6.5; 5]

**Perpendicular Bisector equation:**5x+2y-42.5 = 0

**Vector OA = (4; 4) ; |OA| = 5.6569**

**Vector OB = (9; 6) ; |OB| = 10.8167**

**Scalar product OA .OB = 60**

**Angle ∠ AOB = 11°18'36″ = 0.1974 rad**