# Line slope calculator 6x+10y=100

**Straight line given by points A[0; 10] and B[10; 4]**

## Calculation:

**Slope-intercept form of line:**y = -0.6x+10

**Canonical form of the line equation:**6x+10y-100 = 0

**Parametric form of the line equation:**

x = 10t

y = -6t+10 ; t ∈ R

**Slope:**m = -0.6

**Slope angle of line: φ =**-30°57'50″ = -0.5404 rad

**X intercept:**x

_{0}= 16.6667

**Y intercept:**y

_{0}= q = 10

**Distance line from the origin:**d

_{0}= 8.5749

**The length of the segment AB: |AB| =**11.6619

**Vector: AB =**(10; -6)

**Normal vector: n =**(6; 10)

**Midpoint of the segment AB: M =**[5; 7]

**Perpendicular Bisector equation:**10x-6y-8 = 0

**Vector OA = (0; 10) ; |OA| = 10**

**Vector OB = (10; 4) ; |OB| = 10.7703**

**Scalar product OA .OB = 40**

**Angle ∠ AOB = 68°11'55″ = 1.1903 rad**