Table 1.

Statistical analysis of behavioral and biochemistry data of animals

FactorF valuep value
A. First stage transition between trained groups of animals (one-way ANOVA, α* = 0.05); Fig. 2A
AV sessionF(4,31) = 2.323p = 0.0768
AQ sessionF(2,21) = 1.832p = 0.1847
RT SessionUnpaired Student's t testp = 0.2761
B. Quantification absolute values of BCN ECM-fraction (one-way ANOVA, α* = 0.05); Fig. 3C,D
145 kDa BCN ACxF(5,41) = 3.342p = 0.0127
55 kDa BCN ACxF(5,41) = 3.434p = 0.0111
145 kDa BCN CAF(5,41) = 0.3497p = 0.8795
55 kDa BCN CAF(5,41) = 1.062p = 0.3954
C. Quantification absolute values of TNR ECM-fraction (one-way ANOVA, α* = 0.05); Fig. 4C,D
Full-length TNR ACxF(5,41) = 2.085p = 0.0868
Full-length TNR CAF(5,41) = 1.818p = 0.1306
D. Quantification absolute values of BCN cellular fraction (one-way ANOVA, α* = 0.05); Fig. 3C,D
145 kDa BCN ACxF(5,41) = 1.758p = 0.1433
55 kDa BCN ACxF(5,41) = 15.79p < 0.0001
145 kDa BCN CAF(5,41) = 1.19p = 0.3309
55 kDa BCN CAF(5,41) = 5.221p = 0.0008
E. Quantification absolute values of TNR cellular fraction (one way ANOVA, α* = 0.05); Fig. 4C,D
Full-length TNR ACxF(5,41) = 1.668p = 0,1640
Full-length TNR CAF(5,41) = 1.422p = 0.2367
F. Quantification total levels of BCN (one-way ANOVA, α* = 0.05); Fig. 7A,B
Sum of 55kDa BCN ACxF(5,41) = 14.6p < 0.0001
Sum of 145kDa BCN ACxF(5,41) = 5.567p = 0.0005
Sum of 55kDa BCN CAF(5,41) = 6.377p = 0.0002
Sum of 145kDa BCN CAF(5,41) = 1.632p = 0.1733
G. Quantification total levels of TNR (one-way ANOVA, α* = 0.05); Fig. 7A,B
Sum of full-length TNR ACxF(5,41) = 2.025p = 0.0952
Sum of full-length TNR CAF(5,41) = 3.773p = 0.0067
• All tests were based on significance level of α* = 0.05; for ANOVA post hoc analysis Tukey's tests of multiple comparisons was used. Corresponding figures for tests are indicated.